SPSS第二次作业.docx

1、SPSS第二次作业规定：当样本含量时，结果以Shapiro-Wilk为准。当样本含量时，结果以K-S为准。正态性检验结果显示,其中粤东对应的Shapiro-Wilk检验P值为，所以，粤东的数据分布不服从正态的。同理，粤西的数据也不服从正态分布。Case Processing Summary地区CasesValidMissingTotalNPercentNPercentNPercent降雨量粤东12%0.0%12%粤西12%0.0%12%Descriptives地区StatisticStd. Error降雨量粤东Mean95% Confidence Interval for MeanLower

2、BoundUpper Bound5% Trimmed MeanMedianVarianceStd. DeviationMinimumMaximumRangeInterquartile RangeSkewness.637Kurtosis.487粤西Mean95% Confidence Interval for MeanLower BoundUpper Bound5% Trimmed MeanMedianVarianceStd. DeviationMinimumMaximumRangeInterquartile RangeSkewness.637KurtosisM-Estimators地区Hube

3、rs M-EstimatoraTukeys BiweightbHampels M-EstimatorcAndrews Waved降雨量粤东粤西a. The weighting constant is .b. The weighting constant is .c. The weighting constants are , , and d. The weighting constant is *pi.Extreme Values地区Case NumberValue降雨量粤东Highest13263104758Lowest112531241152粤西Highest114218322413523

4、Lowest117219324420515Tests of Normality地区Kolmogorov-SmirnovaShapiro-WilkStatisticdfSig.StatisticdfSig.降雨量粤东.30212.003.77512.005粤西.22412.098.84912.036a. Lilliefors Significance Correction2.个案处理结果Case Processing SummaryCasesValidMissingTotalNPercentNPercentNPercent升学 * 计数4%0.0%4%交叉表升学 * 计数 Crosstabula

5、tion计数Total16276131143升学0Count11002% within 升学%.0%.0%升学Count00112% within 升学.0%.0%TotalCount11114% within 升学%3不同性别学生之间成绩分析，F统计量的Sig值为大于，所以不可否认方差相等的假设，第一行t检验的值为小于，所以在显著性水平下，认为该班高考不同性别学生成绩无明显差异。Group Statistics性别NMeanStd. DeviationStd. Error Mean高考数学成绩男16女16Independent Samples TestLevenes Test for Equ

6、ality of Variancest-test for Equality of MeansFSig.tdfSig. (2-tailed)Mean DifferenceStd. Error Difference95% Confidence Interval of the DifferenceLower高考数学成绩Equal variances assumed.407.52930.064Equal variances not assumed.0655.描述性统计量Descriptive StatisticsNPercentiles25th50th (Median)75th成绩28国家28频数表F

7、requencies国家A国B国C国D国成绩 Median7700 Median105093105= Median0510179105最后是检验统计量,可以得到卡方统计量为,其对应的P值小于 所以拒绝原假设,即认为这八种饮料的顾客喜爱程度具有显著的差异.Test Statisticsb喜爱程度N80MedianChi-Squaredf7Asymp. Sig.000a. 8 cells %) have expected frequencies less than 5. The minimum expected cell frequency is .b. Grouping Variable: 饮料

8、种类7.描述性的统计量Descriptive StatisticsNMeanStd. DeviationMinimumMaximum每加仑汽油行驶英里数15游程检验结果显示,每加仑汽油行驶英里数标志值的游程为5,由样本计算的检验统计量Z为,P值为,大于,接受原假设, 即认为这5种的差异不明显。Runs Test每加仑汽油行驶英里数Test ValueaCases = Test Value8Total Cases15Number of Runs5ZAsymp. Sig. (2-tailed).110a. Mean8. K-S检验结果的KOS统计量为，对应的P值为大于，所以接受原假设，认为这50名

9、高二学生身高服从正态分布。Descriptive StatisticsNMeanStd. DeviationMinimumMaximum身高50154181One-Sample Kolmogorov-Smirnov Test身高N50Normal Parametersa,bMeanStd. DeviationMost Extreme DifferencesAbsolute.170Positive.078NegativeKolmogorov-Smirnov ZAsymp. Sig. (2-tailed).112a. Test distribution is Normal.b. Calculate

10、d from data.9.有单因素方差分析检验不同包装对饮料销售水平的影响。Levene统计量取值为，Sig取值为，大于，所以认为各组的方差相等。方差分析表显示Sig取值为，即假设成立，认为各组均值没有差异。DescriptivesvolumeNMeanStd. DeviationStd. Error95% Confidence Interval for MeanMinimumMaximumLower BoundUpper Bound包装a110包装a210Total20Test of Homogeneity of VariancesvolumeLevene Statisticdf1df2S

11、ig.031118.862ANOVAvolumeSum of SquaresdfMean SquareFSig.Between Groups1.448.512Within Groups18Total19由单因素方差分析检验不同口味对饮料销售水平的影响。Levene统计量取值为，Sig取值为，大于，所以认为各组的方差相等。方差分析表显示Sig取值为，即假设不成立，认为各组均值有差异。所以认为饮料口味对销售水平影响更大。DescriptivesvolumeNMeanStd. DeviationStd. Error95% Confidence Interval for MeanMinimumMaximumLower BoundUpper Bound口味b110口味b210Total20Test of Homogeneity of VariancesvolumeLevene Statisticdf1df2Sig.015118.904ANOVAvolumeSum of SquaresdfMean SquareFSig.Between Groups1.009Within Groups18Total1910