C语言程序设计慕课下编译答案完美.docx

1、C语言程序设计慕课下编译答案完美 Document serial number【UU89WT-UU98YT-UU8CB-UUUT-UUT108】C语言程序设计慕课下编译答案完美1 求最大公约数和最小公倍数（15分）#include int fun1( int m, int n) 大公约数#include int fun1( int m, int n) 数球和#includeint main() int n; int sum(int n); scanf(%d,&n); printf(%dn,sum(n); int sum(int n) int b; if(n1) b=sum(n-1)+2*n-1

2、; if(n=1) b=1; return b;5.巧算自然数#includeint step = 1;void fc(int n)鸭子#include int main() static int i,x8; x7=2; for(i=7;i=0;i-) xi-1=(xi+1)*2; printf(sum=%dn,x0); for(i=0;i7;i+) printf(sell=%d,xi-xi+1); printf(n); return 0;7.各位数字之和int add(int s) if (s10) return s; else return s%10+add(s/10); int main

3、(int argc, char *argv) int a,b;scanf(%d,&a); b=add(a); printf(%d,b); return 0; 对称字符串#include #include main() char a100; int i,j; gets(a);i=0;j=strlen(a)-1;while(i=j) printf(YESn);else printf(NOn);指针排序#include void sort(int *p,int n); void sort(int *p,int n) int i,j; int temp=0; for(i=0;in;i+) for(j=

4、0;jpj+1) temp=pj; pj=pj+1; pj+1=temp; int main() int i; int a10; for(i=0;i10;i+) scanf(%d,&ai); int *p=a; sort(a,10); for(i=0;i10-1;i+) printf(%d,*(p+); printf(%dn,*p); return 0; 查找数 #include void find(int *p,int element,int n); void find(int *p,int element,int n) int i,flag=0; for(i=0;in;i+) flag+;

5、 if(element = pi) printf(%dn,pi); break; if(flag = n) printf(Non); int main() int i; int a10; for(i=0;i10;i+) scanf(%d,&ai); int *p=a; int num; scanf(%d,&num); find(p,num,10); return 0; 输出指定成绩#include int main() int grade34,i,j,(*p)4=grade,n; float ave=0; for(i=0;i3;i+) for(j=0;j4;j+) scanf(%d,&grad

6、eij); scanf(%d,&n); for(i=0;i3;i+) printf(%d ,*(*(p+n-1)+i); printf(%dn,*(*(p+n-1)+3); for(i=0;i4;i+) ave+=*(*(p+n-1)+i); ave/=4; if(ave-(int)ave) printf(%.2fn,ave); else printf(%dn,(int)ave); return 0;成绩排序#include void average(int p6,int n); void average(int p6,int n) int i; for(i=0;imax2 & max1max

7、3) if(max2max3) printf(%d,%d,%d,%dn,p00,p01,p02,p03); printf(%d,%d,%d,%dn,p10,p11,p12,p13); printf(%d,%d,%d,%dn,p20,p21,p22,p23); else printf(%d,%d,%d,%dn,p00,p01,p02,p03); printf(%d,%d,%d,%dn,p20,p21,p22,p23); printf(%d,%d,%d,%dn,p10,p11,p12,p13); else if(max2max1 & max2max3) if(max1max3) printf(%d

8、,%d,%d,%dn,p10,p11,p12,p13); printf(%d,%d,%d,%dn,p00,p01,p02,p03); printf(%d,%d,%d,%dn,p20,p21,p22,p23); else printf(%d,%d,%d,%dn,p10,p11,p12,p13); printf(%d,%d,%d,%dn,p20,p21,p22,p23); printf(%d,%d,%d,%dn,p00,p01,p02,p03); else if(max3max1 & max3max2) if(max1max2) printf(%d,%d,%d,%dn,p20,p21,p22,p2

9、3); printf(%d,%d,%d,%dn,p00,p01,p02,p03); printf(%d,%d,%d,%dn,p10,p11,p12,p13); else printf(%d,%d,%d,%dn,p20,p21,p22,p23); printf(%d,%d,%d,%dn,p10,p11,p12,p13); printf(%d,%d,%d,%dn,p00,p01,p02,p03); int main() int i,j; int a36=0; for(i=0;i3;i+) for(j=0;j4;j+) scanf(%d,&aij); average(a,i); Print(a,3)

10、; return 0; 统计字符串出现次数#include #include int main() char str1100,str2100; int flag=0,counter=0,l1,l2,i,j; gets(str1);gets(str2); l1=strlen(str1);l2=strlen(str2); for(i=0;il1;i+) if(str1i=str20) for(j=1;jl2;j+) if(str1i+j!=str2j) break; else flag=1; if(flag) counter+; if(counter) printf(%dn,counter); e

11、lse printf(Non); return 0;成绩统计求平均分#includemain()printf(wanglei,n);printf(lihong,n);printf(zhangli,n);printf(liuming,83n);printf(AVERAGE:,82n);加密#include#includeint l;void gm(char*a);main() char s100=0; gets(s); l=strlen(s); gm(s);void gm(char*a) int i; char d100=0; for(i=0;il;i+) switch(ai) casea:di

12、=d;break; caseb:di=w;break; casec:di=k;break; cased:di=;break; casee:di=i;break; casei:di=a;break; casek:di=b;break; case;:di=c;break; casew:di=e;break; default:di=ai; puts(d);学生成绩#includestruct adeint no;int am;int bm;int cm;struct ade N3=1,70,80,90,2,75,85,95,3,88,84,65;main() char s300;int i=0,k,

13、m; for(i=0;i3;i+) scanf(%c,&si); if(si=n) break; if(s0=m)printf(2); else if(s0=1|s0=2|s0=3)k=N(int)(s0-1).am+N(int)(s0-1).bm+N(int)(s0-1).cm;m=k/3;printf(%d,m); else printf(0);字母储存#include #include typedef struct Char_ char ch; char intch; struct Char_ *next; CHAR_; int main(void) CHAR_ *node = NULL

14、; CHAR_ *ch_ = NULL; CHAR_ *hear = NULL; char zimu = a; char panduanzimu; char record;for (; zimu != e; zimu+) ch_ = (CHAR_ *)malloc(sizeof(CHAR_); if (ch_ = NULL) exit(0); ch_-ch = zimu; ch_-next = NULL; if (node = NULL) node = ch_; else node-next = ch_; node = node-next; if (hear = NULL) hear = no

15、de; for (zimu -= 2; zimu != (a - 1); zimu-) ch_ = (CHAR_ *)malloc(sizeof(CHAR_); if (ch_ = NULL) exit(0); ch_-ch = zimu; ch_-next = NULL; node-next = ch_; node = node-next; for (node = hear, zimu = 0; node != NULL; node = node-next, zimu+) node-intch = zimu; scanf(%c, &panduanzimu); node = hear; if

16、(panduanzimu = 0&panduanzimu intch) printf(%c, node-ch); break; node = node-next; else if (panduanzimu = a&panduanzimu ch) record = node-intch; node = node-next; printf(%c, record); else printf(N); node = hear; while (node != NULL) hear = node-next; free(node); node = hear; return 0; 链表合并#include#in

17、cludeint main() static int i,j,m,n; static char q,x100,y100,z100; gets(x);gets(y); strcat(x,y); m=strlen(x); for(j=0;jm;j+) for(i=0;ixj+i) xj=xj+i; xj+i=q; for(i=0;im;i+) for(j=0;j0;i-) if(isalpha(zi) m=i; break; for(i=0;i=m;i+) if(zi= ) continue; else if(i=m) printf(%cn,zi); else printf(%c ,zi); re

18、turn 0;解析字符串#include #include int main() int i,j,k=0; char a100,b100,c100; gets(a); for(i=0;ai!=n;i+) printf(%c,ai); k+; printf(n); for(i=k+1;ai!=0&ai!=n;i+) printf(%c,ai); k+; if(ai=n&ai+1!=0) for(i=k+2;ai!=0;+i) printf(%c,ai); 字符串反向#include#include int main ( ) char str80, c; int i, j, n; gets(str

19、); n = strlen(str); for ( i=0, j=n-1; ij; i+, j- ) c= stri; stri = strj; strj = c; puts(str);return 0;基本的四则运算#include int main() long long a,b; char op; scanf(%lld%c%lld,&a,&op,&b); switch(op) case +: printf(%lldn,a+b); break; case -: printf(%lldn,a-b); break; case *: printf(%lldn,a*b); break; case

20、/: printf(%lldn,a/b); break; case %: printf(%lldn,a%b); break; return 0;复杂的四则运算#include #include int main() static char x100; int i; scanf(%s,&x); for(i=0;i=0&xi=9) continue; if(xi=*) xi-1=(xi-1-0)*(xi+1-0)+0; xi+1=0; i+; else if(xi=/) xi-1=(xi-1-0)/(xi+1-0)+0; xi+1=0; i+; for(i=1;i=0&xi=9) if(xi-1=+) x0+=(xi-0); else if(xi-1=-) x0-=(xi-0); else continue; printf(%cn,x0); return 0;