1、goutput:2利用matlab实现食饵与捕食者系统的仿真:Volterra食饵与捕食者模型:取 shier.mfunction,dx=shier(t,x)global,r,d,a,b;dx=zeros(2,1);dx(1)=(r-a*x(2)*x(1)dx(2)=(-d+b*x(1)*x(2) shier2.mr=1;d=0.5;a=0.1;b=0.02;ts=0:0.1:15;x0=25,2;t,x=ode45(shier,ts,x0);plot(x(:,1),x(:,2)3. 利用matlab实现两种群共生系统的仿真:仿照上例编写程序。input:peace.mfunction,dx=
2、peace(t,x)global,N1,N2,r1,r2,q1,q2;dx(1)=r1*x(1)*(1-x(1)./N1+q1*x(2)./N2)dx(2)=r2*x(2)*(-1+q2*x(1)./N1-x(2)./N2)peace2.mN1=input(种群1最大容量=,);n1=input(种群1初始数量=,N2=input(种群2最大容量=,n2=input(q1=input(请输入相关系数q1=q2=input(请输入相关系数q2=r1=0.05;r2=0.01;1:5000;x0=n1,n2;peace%plot(x(:plot(t,x(:rresult:取N1=100,N2=20
3、0,n1=10,n2=20,q1=0.3,q2=34.,利用matlab实现两种群的竞争系统的仿真:Input: fight.mfunction,dx=fight(t,x)dx(1)=r1*x(1)*(1-x(1)./N1-q1*x(2)./N2)dx(2)=r2*x(2)*(1-q2*x(1)./N1-x(2)./N2)%dx(1)=r1*x(1)*(1-x(1)./N1)%dx(2)=r2*x(2)*(1-x(2)./N2) fight2.mfight取N1=100,N2=200,n1=10,n2=20,q1=0.3,q2=0.5实验二:社会经济系统的冲量过程分析1 熟练matlab的基本
4、函数,掌握矩阵运算的函数使用:矩阵,matrix_1.mA=,1,2,3;,4,5,6;,7,8,9;B=,1,1,1;,2,2,2;,3,3,3;ABdisp(1)矩阵的加减C=A+BD=A-B(2)矩阵的乘法E=A*B(3)矩阵的逆运算inv(A)4)矩阵的幂运算A3(5)矩阵的特征值函数(x为特征向量矩阵,y为特征值矩阵F=,7,3,-2;,3,4,-1;,-2,-1,3;Fx,y=eig(F)(6)矩阵的转置F(6)矩阵的除法A右除BA/BA左除BABoutput:A,=,1,2,3,4,5,6,7,8,9B,=,1,1,1,2,2,2,3,3,3(1)矩阵的加减C,=,2,3,4,6
5、,7,8,10,11,12D,=,0,1,2(2)矩阵的乘法E,=,14,14,14,32,32,32,50,50,50(3)矩阵的逆运算Warning:,Matrix,is,close,to,singular,or,badly,scaled.,Results,may,be,inaccurate.,RCOND,=,1.541976e-018.,In,F:MATLAB6p5workmatrix_1.m,at,line,15ans,=,1.0e+016,*,-0.4504,0.9007,-0.4504,0.9007,-1.8014,0.90074)矩阵的幂运算,468,576,684,1062,1
6、305,1548,1656,2034,2412(5)矩阵的特征值函数(x为特征向量矩阵,y为特征值矩阵F,=,7,3,-2,3,4,-1,-2,-1,3x,=,0.5774,-0.0988,-0.8105,-0.5774,0.6525,-0.4908,0.5774,0.7513,0.3197y,=,2.0000,0,0,0,2.3944,0,0,0,9.6056(6)矩阵的转置(6)矩阵的除法A右除B,Matrix,is,singular,to,working,precision.(Type,warning,off,MATLAB:singularMatrix,to,suppress,this,
7、warning.)MATLAB6p5workmatrix_1.m,at,line,32,Inf,Inf,InfA左除BnearlySingularMatrixMATLAB6p5workmatrix_1.m,at,line,34,-0.3333,-0.3333,-0.3333,0.6667,0.6667,0.6667,0,0,02 分析社会经济系统的演化第一步,输入能源经济系统有向图的邻接矩阵A;第二步,计算;第三步,分析变化的规律,画出系统中每个变量随时间变化的增减趋势图。ex_2.mA=0,-1,1,-1,0,0,0;-1,0,0,0,0,0,0;0,-1,0,0,1,0,0;0,0,0,0
8、,0,0,1;1,0,0,0,0,1,0;1,0,0,0,0,0,0B=A;for,i=2:10%sprintf(A的%d次幂为,i)B=cat(4,B,Ai);endrow=input(要查看变量元素的行数=line=input(要查看变量元素的列数=temp=zeros(1,10);for,j=1:C=B(:,:,1,j);temp(1,j)=C(row,line);temp变化图形如下plot(1:10,temp)x,y=eig(A);Output:,察看1,2号元素的变化,0,-1,1,-1,0,0,0,-1,0,0,0,0,0,0,0,-1,0,0,1,0,0,0,0,0,0,0,0
9、,1,1,0,0,0,0,1,0,1,0,0,0,0,0,0B(:,1,1),=,1,2),=,1,-1,0,0,1,0,-1,0,1,-1,1,0,0,0,2,0,0,0,0,1,0,0,-1,1,-1,0,0,1,1,3),=,1,-1,1,-1,0,1,0,-1,1,0,0,-1,0,1,0,-2,2,-2,0,0,1,2,-1,0,0,1,0,-1,1,4),=,1,-2,1,-1,1,0,0,-1,1,-1,1,0,-1,0,3,-2,0,0,2,0,-2,1,-2,2,-2,0,1,0,1,5),=,3,-2,1,-1,1,1,-1,-1,2,-1,1,-1,0,0,2,-3,3,
10、-3,0,2,0,2,-3,1,-1,2,0,-1,1,6),=,2,-4,3,-3,1,1,0,-3,2,-1,1,-1,-1,1,3,-5,2,-2,3,0,-1,4,-3,2,-2,1,2,-1,1,7),=,5,-5,2,-2,3,1,-2,-2,4,-3,3,-1,-1,0,7,-5,3,-3,2,3,-2,3,-6,4,-4,2,1,0,1,8),=,6,-7,5,-5,2,3,-1,-5,5,-2,2,-3,-1,2,5,-10,7,-7,3,2,0,8,-7,3,-3,4,2,-3,1,9),=,8,-11,6,-6,5,2,-2,-6,7,-5,5,-2,-3,1,13,-1
11、2,5,-5,7,3,-5,8,-11,8,-8,3,4,-1,1,10),=,14,-14,8,-8,6,5,-4,-8,11,-6,6,-5,-2,2,14,-18,13,-13,5,7,-2,13,-16,8,-8,8,3,-4要查看变量元素的行数=1要查看变量元素的列数=2temp,=,-1,-1,-1,-2,-2,-4,-5,-7,-11,-14变化图形如下实验三:软件开发人员的薪金问题分析利用统计工具箱,完成软件开发人员的薪金问题的分析(1) 原始模型function,wage=wage(X,Y)A=1,1,1,0;1,0,0,0;1,1,0,0;1,0,0,1;2,1,0,1;2
12、,0,0,1;2,0,1,0;2,0,0,0;3,0,0,1;3,1,1,0;3,1,0,1;3,1,0,0;,4,0,1,0;4,1,0,0;4,0,0,0;4,0,0,1;5,0,0,1;5,0,0,0;5,1,1,0;6,0,1,0;6,1,0,0;6,0,0,1;6,1,0,1;7,1,1,0;8,0,0,1;,8,1,1,0;8,1,0,0;8,0,1,0;10,0,1,0;10,0,0,1;10,1,0,0;10,1,0,1;11,1,0,1;11,0,1,0;12,0,0,1;,12,1,0,0;13,0,1,0;13,1,0,1;14,0,0,1;15,1,0,0;16,1,0
13、,1;16,0,0,1;16,0,1,0;17,0,0,1;20,0,1,0;X=ones(46,1),AY=13876;11608;18701;11283;11767;20872;11772;10535;12195;12313;14975;21371;19800;,11417;20263;13231;12884;13245;13677;15965;12366;21352;13839;22884;16978;14803;,17404;22184;13548;14467;15942;23174;23780;25410;14861;16882;,24170;15990;26330;17949;25
14、685;27837;18838;17483;19207;19346b,bint,r,rint,stats=regress(Y,X);,%求回归系数的点估计b和区间估计bintb,%求点估计bbint,%求区间估计bintstats,%stats由,(1)相关系数R2,(2)F值,(3)对应概率figurercoplot(r,rint),%画出残差r和置信区间rintplot(A(:,1),r,k+),%模型(1)残差r和x1的关系b,=,1.0e+004,*,1.1033,0.0546,0.6883,-0.2994,0.0148bint,=,1.0258,1.1807,0.0484,0.0608,0.6248,0.7517,-0.3826,-0.2162,-0.0636,0.0931stats,=0.9567,226.4258,0(2) 修改模型,Input:function,wage2=wage2(X,Y)5,0,
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