break;
end
end
x
结果
Jacobi迭代法
L=
000
100
110
D=
200
010
002
U=
011
001
000
M=
0.500000
01.00000
000.5000
x=
0
0
0
x=
1.0e+005*
Columns1through4
00-0.0000-0.0000
00.00000.00000.0001
00.0000-0.00000.0000
Columns5through8
-0.0000-0.0000-0.0000-0.0000
0.00000.00010.00000.0001
-0.00000.0000-0.00000.0000
Columns9through12
-0.00010.0000-0.00010.0000
0.00000.00010.00000.0002
-0.00000.0000-0.00010.0000
Columns13through16
-0.00010.0001-0.00020.0001
-0.00000.0002-0.00010.0003
-0.00010.0001-0.00010.0001
Columns17through20
-0.00020.0002-0.00040.0004
-0.00020.0005-0.00040.0007
-0.00020.0002-0.00040.0004
Columns21through24
-0.00060.0007-0.00090.0011
-0.00080.0012-0.00130.0019
-0.00060.0007-0.00090.0011
Columns25through28
-0.00150.0019-0.00240.0031
-0.00220.0030-0.00370.0049
-0.00150.0019-0.00240.0031
Columns29through32
-0.00400.0050-0.00650.0083
-0.00610.0080-0.01000.0131
-0.00400.0050-0.00650.0083
Columns33through36
-0.01070.0136-0.01750.0223
-0.01650.0214-0.02720.0350
-0.01070.0136-0.01750.0223
Columns37through40
-0.02870.0366-0.04700.0601
-0.04460.0573-0.07330.0940
-0.02870.0367-0.04700.0601
Columns41through44
-0.07710.0987-0.12640.1619
-0.12020.1542-0.19730.2529
-0.07710.0987-0.12640.1619
Columns45through48
-0.20740.2655-0.34010.4356
-0.32370.4147-0.53100.6803
-0.20740.2655-0.34010.4356
Columns49through51
-0.55790.7145-0.9152
-0.87111.1159-1.4290
-0.55790.7145-0.9152
Gauss-Seidel迭代法
L=
000
100
110
D=
200
010
002
U=
011
001
000
M=
0.500000
01.00000
000.5000
x=
0
0
0
x=
Columns1through6
00-1.0000-1.7500-2.2500-2.5625
03.00005.00006.25007.00007.4375
0-1.0000-1.5000-1.7500-1.8750-1.9375
Columns7through12
-2.7500-2.8594-2.9219-2.9570-2.9766-2.9873
7.68757.82817.90637.94927.97277.9854
-1.9688-1.9844-1.9922-1.9961-1.9980-1.9990
Columns13through18
-2.9932-2.9963-2.9980-2.9990-2.9995-2.9997
7.99227.99587.99787.99887.99947.9997
-1.9995-1.9998-1.9999-1.9999-2.0000-2.0000
题目
2、(P75第15题)设方程组
给定
用Gauss-Seidel迭代法和
的SOR方法求解该方程组,精确到
.
程序
(将程序粘贴在此)
结果
(将结果粘贴在此)
完成日期:
2014/3/20