计算机安全学上机题目与答案Word文件下载.docx
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inti=200962035;
intn,p[10];
intj=9;
intk1=3,k0=2;
加密:
p=i*k1+k0"
while(i!
n=i%10;
i=i/10;
p[j]=(k1*n+k0)%10;
j--;
}
加密结果"
for(inti1=1;
i1<
10;
i1++)
{cout<
p[i1];
}
endl<
解密输入:
inta,n1,pp[10];
intj1=9;
cin>
a;
while(a!
n1=a%10;
a=a/10;
pp[j1]=7*(n1+8)%10;
j1--;
解密结果:
for(inti2=1;
i2<
i2++)
pp[i2];
3.中国剩余定理代码
//求模逆
intmodni(inta,intp)
inttemp,sign,sign2,g;
sign=0;
sign2=0;
if(a%p==0)
没有逆模"
if(a<
0)
{a=a+p;
sign2=1;
if(a/p<
a%p)
{a=p-a;
}
elseif(a/p<
a%p)
{a=(-1)*a;
if(a<
0)
{a=p+a;
sign2=1;
p)
{sign=1;
temp=a;
a=p;
p=temp;
ints=1,u=0,t=0,v=1;
intr=a%p,w,q=a/p;
while(a%p)
r=a%p;
q=a/p;
p=r;
w=u;
u=s-q*u;
s=w;
w=v;
v=t-q*v;
t=w;
g=p;
if(g!
=1)
elseif(g==1)
{
if(sign2==1)
if(sign==1)
{v=(-1)*v;
//v=zhfu(v,p);
returnv;
else
{u=(-1)*u;
//u=zhfu(u,p);
returnu;
elseif(sign2==0)
elseif(sign==0)
//u=zhfu(u,p);
return0;
voidmain()
我的学号:
035"
a1=035,a2=3,a3=4,m1=199,m2=5,m3=11"
inta1=35,a2=3,a3=4,m1=199,m2=5,m3=11;
intM=m1*m2*m3;
intM1=m2*m3,M2=m1*m3,M3=m1*m2;
intb1=modni(M1,m1);
if(b1<
0)b1=b1+m1;
intb2=modni(M2,m2);
if(b2<
0)b1=b2+m2;
intb3=modni(M3,m3);
if(b3<
0)b1=b3+m3;
intx=a1*b1*M1+a2*b2*M2+a3*b3*M3;
x=x%M;
结果:
x<
4.des算法代码
fstream>
conststaticcharip[]={
58,50,42,34,26,18,10,2,
60,52,44,36,28,20,12,4,
62,54,46,38,30,22,14,6,
64,56,48,40,32,24,16,8,
57,49,41,33,25,17,9,1,
59,51,43,35,27,19,11,3,
61,53,45,37,29,21,13,5,
63,55,47,39,31,23,15,7
};
conststaticcharfp[]={
40,8,48,16,56,24,64,32,
39,7,47,15,55,23,63,31,
38,6,46,14,54,22,62,30,
37,5,45,13,53,21,61,29,
36,4,44,12,52,20,60,28,
35,3,43,11,51,19,59,27,
34,2,42,10,50,18,58,26,
33,1,41,9,49,17,57,25
conststaticcharsbox[8][64]={
/*S1*/
14,4,13,1,2,15,11,8,3,10,6,12,5,9,0,7,
0,15,7,4,14,2,13,1,10,6,12,11,9,5,3,8,
4,1,14,8,13,6,2,11,15,12,9,7,3,10,5,0,
15,12,8,2,4,9,1,7,5,11,3,14,10,0,6,13,
/*S2*/
15,1,8,14,6,11,3,4,9,7,2,13,12,0,5,10,
3,13,4,7,15,2,8,14,12,0,1,10,6,9,11,5,
0,14,7,11,10,4,13,1,5,8,12,6,9,3,2,15,
13,8,10,1,3,15,4,2,11,6,7,12,0,5,14,9,
/*S3*/
10,0,9,14,6,3,15,5,1,13,12,7,11,4,2,8,
13,7,0,9,3,4,6,10,2,8,5,14,12,11,15,1,
13,6,4,9,8,15,3,0,11,1,2,12,5,10,14,7,
1,10,13,0,6,9,8,7,4,15,14,3,11,5,2,12,
/*S4*/
7,13,14,3,0,6,9,10,1,2,8,5,11,12,4,15,
13,8,11,5,6,15,0,3,4,7,2,12,1,10,14,9,
10,6,9,0,12,11,7,13,15,1,3,14,5,2,8,4,
3,15,0,6,10,1,13,8,9,4,5,11,12,7,2,14,
/*S5*/
2,12,4,1,7,10,11,6,8,5,3,15,13,0,14,9,
14,11,2,12,4,7,13,1,5,0,15,10,3,9,8,6,
4,2,1,11,10,13,7,8,15,9,12,5,6,3,0,14,
11,8,12,7,1,14,2,13,6,15,0,9,10,4,5,3,
/*S6*/
12,1,10,15,9,2,6,8,0,13,3,4,14,7,5,11,
10,15,4,2,7,12,9,5,6,1,13,14,0,11,3,8,
9,14,15,5,2,8,12,3,7,0,4,10,1,13,11,6,
4,3,2,12,9,5,15,10,11,14,1,7,6,0,8,13,
/*S7*/
4,11,2,14,15,0,8,13,3,12,9,7,5,10,6,1,
13,0,11,7,4,9,1,10,14,3,5,12,2,15,8,6,
1,4,11,13,12,3,7,14,10,15,6,8,0,5,9,2,
6,11,13,8,1,4,10,7,9,5,0,15,14,2,3,12,
/*S8*/
13,2,8,4,6,15,11,1,10,9,3,14,5,0,12,7,
1,15,13,8,10,3,7,4,12,5,6,11,0,14,9,2,
7,11,4,1,9,12,14,2,0,6,10,13,15,3,5,8,
2,1,14,7,4,10,8,13,15,12,9,0,3,5,6,11
conststaticcharrar[]={
14,17,11,24,1,5,
3,28,15,6,21,10,
23,19,12,4,26,8,
16,7,27,20,13,2,
41,52,31,37,47,55,
30,40,51,45,33,48,
44,49,39,56,34,53,
46,42,50,36,29,32
conststaticcharei[]={
32,1,2,3,4,5,
4,5,6,7,8,9,
8,9,10,11,12,13,
12,13,14,15,16,17,
16,17,18,19,20,21,
20,21,22,23,24,25,
24,25,26,27,28,29,
28,29,30,31,32,1
conststaticcharPzh[]={
16,7,20,21,
29,12,28,17,
1,15,23,26,
5,18,31,10,
2,8,24,14,
32,27,3,9,
19,13,30,6,
22,11,4,25
conststaticcharKeyrar[]={
57,49,41,33,25,17,9,
1,58,50,42,34,26,18,
10,2,59,51,43,35,27,
19,11,3,60,52,44,36,
63,55,47,39,31,23,15,
7,62,54,46,38,30,22,
14,6,61,53,45,37,29,
21,13,5,28,20,12,4
boolkey[16][48]={0},
charkey_in[8];
voidByteToBit(bool*Out,char*In,intbits)
inti;
for(i=0;
i<
bits;
i++)
Out[i]=(In[i/8]>
(i%8))&
1;
voidBitToByte(char*Out,bool*In,intbits)
for(inti=0;
bits/8;
Out[i]=0;
Out[i/8]|=In[i]<
(i%8);
voidXor(bool*InA,constbool*InB,intlen)
len;
InA[i]^=InB[i];
voidkeyfc(char*In)
inti,j=0,mov,k;
boolkey0[56],temp,keyin[64];
ByteToBit(keyin,In,64);
56;
i++)
key0[i]=keyin[Keyrar[i]-1];
16;
if(i==0||i==1||i==8||i==15)
mov=1;
else
mov=2;
for(k=0;
k<
mov;
k++)
{
for(intm=0;
m<
8;
m++)
{
temp=key0[m*7];
for(j=m*7;
j<
m*7+7;
j++)
key0[j]=key0[j+1];
key0[m*7+6]=temp;
temp=key0[0];
for(m=0;
27;
key0[m]=key0[m+1];
key0[27]=temp;
temp=key0[28];
for(m=28;
55;
key0[55]=temp;
}
for(j=0;
48;
j++)
key[i][j]=key0[rar[j]-1];
voidDES(charOut[8],charIn[8],boolMS)
boolMW[64],tmp[32],PMW[64];
boolkzmw[48],keytem[48],ss[32];
inthang,lie;
ByteToBit(PMW,In,64);
for(intj=0;
64;
MW[j]=PMW[ip[j]-1];
bool*Li=&
MW[0],*Ri=&
MW[32];
i++)
kzmw[i]=Ri[ei[i]-1];
if(MS==0)
for(intlun=0;
lun<
lun++)
for(i=0;
32;
ss[i]=Ri[i];
kzmw[i]=Ri[ei[i]-1];
keytem[i]=key[lun][i];
Xor(kzmw,keytem,48);
hang=kzmw[i*6]*2+kzmw[i*6+5];
lie=kzmw[i*6+1]*8+kzmw[i*6+2]*4+kzmw[i*6+3]*2+kzmw[i*6+4];
tmp[i*4+3]=sbox[i][(hang+1)*16+lie]%2;
tmp[i*4+2]=(sbox[i][(hang+1)*16+lie]/2)%2;
tmp[i*4+1]=(sbox[i][(hang+1)*16+lie]/4)%2;
tmp[i*4]=(sbox[i][(hang+1)*16+lie]/8)%2;
for(inti=0;
i++)
Ri[i]=tmp[Pzh[i]-1];
Xor(Ri,Li,32);
i++)
Li[i]=ss[i];
for(i=0;
tmp[i]=Li[i];
Li[i]=Ri[i];
Ri[i]=tmp[i];
PMW[i]=MW[fp[i]-1];
BitToByte(Out,PMW,64);
else
for(intlun=15;
lun>
=0;
lun--)
ss[i]=Ri[i];
for(inti=0;
kzmw[i]=Ri[ei[i]-1];
keytem[i]=key[lun][i];
Xor(kzmw,keytem,48);
hang=kzmw[i*6]*2+kzmw[i*6+5];
lie=kzmw[i*6+1]*8+kzmw[i*6+2]*4+kzmw[i*6+3]*2+kzmw[i*6+4];
tmp[i*4+3]=sbox[i][(hang+1)*16+lie]%2;
tmp[i*4+2]=(sbox[i][(hang+1)*16+lie]/2)%2;
tmp[i*4+1]=(sbox[i][(hang+1)*16+lie]/4)%2;
tmp[i*4]=(sbox[i][(hang+1)*16+lie]/8)%2;
Ri[i]=tmp[Pzh[i]-1];
Xor(Ri,Li,32);
}
charKi[]="
12345678"
jm[]="
00962035"
final[8];
inti0;
请输入密钥:
学号:
00962035加密"
keyfc(Ki);
//cout<
请输入明文:
//for(i0=0;
i0<
i0++)
//ci
DES(final,jm,0);
加密后:
//加密
for(i0=0;
final[i0];
解密后:
DES(jm,final,1);
//解密
for(i0=0;
jm[i0];
5.rsa算法代码
intcandp(inta,intb,intc)
{intr=1;
b=b+1;
while(b!
r=r*a;
r=r%c;
b--;
printf("
%d\n"
r);
returnr;
intp=23,q=31,e=29,d=569,m=35,n,c,m1;
n=p*q;
c=candp(m,e,n);
密文为:
c<
m1=candp(c,d,n);
明文为:
m1<
运算结果:
5.Md5算法
#include<
cstring>
#defineF(x,y,z)(((x)&
(y))|((~x)&
(z)))
#defineG(x,y,z)(((x)&
(z))|((y)&
(~z)))
#defineH(x,y,z)((x)^(y)^(z))
#defineI(x,y,z)((y)^((x)|(~z)))
#defineRL(x,y)(((x)<
(y))|((x)>
(32-(y))))
#definePP(x)(x<
24)|((x<
8)&
0xff0000)|((x>
0xff00)|(x>
24)
#defineFF(a,b,c,d,x,s,ac)a=b+(RL((a+F(b,c,d)+x+ac),s))
#defineGG(a,