人教版小学数学六年级期末复习重点难点知识点.docx

人教版小学数学六年级期末复习重点难点知识点.docx

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人教版小学数学六年级期末复习重点难点知识点

人教版小学数学六年级期末复习重点难点知识点_XX知道（Knowthesixthgradeprimaryschoolmathematicsreviewofkeyanddifficultknowledgepoints_Baiduteach）

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Baiduknows[education/Science]primaryschooleducation

PEPedition,primarymathematics,gradesix,finalreview,keypoints,difficulties,knowledgepoints

Views:

1117rewardpoints:

50|questiontime:

2009-12-1219:

20|questionger:

whyisclosed|arrivehappiness

Tolist,torecite,torefine.Problemsupplement:

Morepopular,Icanunderstand,please.

Itisbettertoadd3simpletodifficultquestionsatthebackofeachknowledgepoint.

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Thereare4otheranswers

1numberpercopy=total

Thetotalnumberofcopiesper=.

Thetotalnumberofcopiesofeachnumber=.

21multiples*multiples=multiples

Afewtimes,1timestimes=

Afewtimes,ratio=1times

3speedxtime=distance

Distance/speed=time

Time=distance/speed

4unitprice=quantity=totalprice

Price/price=number

Thetotalnumberof83019=price

5workefficiency*workinghours=workamount

Thetotalamountofwork,workefficiency=workingtime

Thetotalamountofwork,worktime=workefficiency

6addendaddend=+and

Anda=otheraddendaddend

7-meiosisdifference=minuend

Minuend-difference=meiosis

Poor+=subtrahendminuend

8factorXfactor=product

Product,afactor=anotherfactor

9dividend,divisor=Business

Dividend,divisor=Business

Quotient*divisor=divisor

Mathematicalformulasforelementaryschoolmathematics

1squares

Cperimeter,Sarea,asidelength

Circumference=sidelength*4

C=4a

Area=sidelength*sidelength

S=a*a

2.

V:

volumea:

edgelength

Surface=edgelengthxxx*6

Stable=axa*6

Volume=edgelengthxedgelongxedgelength

V=a*a*a

3rectangle

Cperimeter,Sarea,asidelength

Circumference=（length+width）*2

C=2（a+b）

Area=length*width

S=ab

4cuboid

V:

volumes:

areaa:

long,b:

width,h:

height

（1）surfacearea（length*width+length*height+width*height）*2

S=2（ab+ah+bh）

（2）volume=**width*height

V=abh

5triangle

Sareaa,bottomhhigh

Bottomarea=xheight/2

S=ah/2

Triangleareahigh=x2/bottom

Trianglearea=x2/high

6parallelogram

Sareaa,bottomhhigh

Area=base*height

S=ah

7trapezoid

Sareaa,bottomB,bottomhhigh

Area=（+downonthebottomend）*/2

S=（a+b）*H/2

8round

SC-d=r=diameter,perimeterarearadius

（1）==2***perimeterdiameterpi*radius

C=IId=2IIR

（2）***area=radiusradius

9cylinder

V:

volumeh:

highS;bottomarear:

;baseradiusc:

;bottomperimeter

（1）thesidearea=thecircumferenceofthebottom*high

（2）surfacearea=sidearea+basearea*2

（3）volume=basearea*height

（4）=2/Xvolumesidearearadius

10cone

V:

volumeh:

highS;basearear:

bottomradius

Volume=bottomareaxheight/3

Thetotal,thetotalnumberofcopies=averagenumber

Equationofsumanddifference

（+anddifference）830192=number

（andpoor）830192=decimal

Doublingproblem

And（1=decimalmultiples）.

Decimal=multiple=largenumber

（orsum=decimal=largenumber）

Differenceproblem

（1/differencemultiples）=decimal

Decimal=multiple=largenumber

（ordecimal+difference=largenumber）

Treeplantingproblem

1,theproblemoftreeplantingonnonclosedlinescanbedividedintothefollowingthreecases:

Ifanonclosedlineatbothendsareplantingtrees,so:

Number=numberof+1/1=lengthspacing

*（1=lengthspacingnumber）

Fulllength（1/spacing=number）

Ifyouwanttoplanttreesintheendofnonclosedline,theotherendisnotplanting,so:

Number=number=length/spacing

Length=xnumberofrows

=length/numberofrows

Ifbothendsinnonclosedlinearenotplantingtrees,so:

Numbersectionnumber=-1/1=lengthspacing

*（number=lengthspacing+1）

=length/spacing（number1）

2thenumberoftreesonclosedlinesisasfollows

Number=number=length/spacing

Length=xnumberofrows

=length/numberofrows

Profitandloss

（profit+loss）,thetwodistributionofthedifferencebetweenthenumberofcopiesinthedistributionof=

（largesurplus-smallsurplus）/twodistributionofthedifferencebetweenthenumberofcopiesinthedistributionof=

（burned-asmalllossoftwotimes）,thedifferencebetweenthenumberofcopiesisassignedtoparticipateinthedistributionofthe

Encounterproblem

Encounterdistance=speedandXmeetingtime

Meettime=distance/speedandmeet

Thespeedanddistance,theencountertime=meet

Catchupwithproblems

Trackingdistance=speeddifference*trackingtime

Chaseandchaseanddistance/time=speeddifference

Thespeeddifferenceanddistance=chasechaseandtime.

Flowproblem

Downstreamvelocity=hydrostaticvelocity+flowvelocity

Countercurrentvelocity=hydrostaticvelocity-flowvelocity

Hydrostaticspeed=（downstreamvelocityandvelocity）,2

Flowrate=（downstreamspeedvelocity）,2

Concentrationproblem

Theweightofthesolute+theweightofthesolvent=theweightofthesolution

Theweight,theweightofthesolutesolutionx100%=concentration

Weightofsolution=concentration=soluteweight

Theweight,concentrationofsolutesolution=weight

Profitanddiscountproblems

Profit=sellingprice-cost

Therateofprofit,profit=costX100%=（sold/cost1）*100%

Amountoffluctuation=principal*ChangePercentage

Theactualpricediscount,theoriginalpricex=100%（<1discount）

Interest=principal*interestrate*time

Aftertaxinterestrates***=principaltime（120%）

1,100ml（1.5cm3）=M=（）.

1500DM3=（M3）

2,acylindricalbottomdiameteris4cm,10cmhigh,itssideareais（）squarecentimeter,volumeis（）cubiccentimeter.

3,dosomecylindricalironpipe,howmanyironsheetsarerequired,thatis,toaskforit.Askinghowmuchwaterthepipecanholdisaskingforit.

5.Digacylindricalpoolontheground.Thedepthofthepoolis4meters.Thediameteris6meters.Thepoolcoversanareaofsquaremetersandneedscubicmetersofearth.

6.Spreadthesidesofacylindertogetasquare.Theradiusofthebottomofthiscolumnis2cm,andtheheightofthecylinderis（）cm,itsvolumeis（）cubiccentimeter.

Two,goodreferee.（10points）

1,thelateralexpansionofthecylindercangetarectangle,thelengthofthisrectangleisequaltothecircumferenceofthebottomofthecylinder,andthewidthisequaltotheheightofthecolumn.（）

2.Acylinderwitharadiusof2meters.Itsbottomcircumferenceisequaltoitsbasearea.（）

3,thebrokenlinestatisticalchartismorelikelytoseetherelationshipbetweenthepartsandthewhole.（）

Three.Writetheserialnumberofthecorrectanswerinbrackets（10points）

1,suchashighattheendofacylindrical,square,rectangularvolumecomparison,（）

A.cubecuboidB.largevolume;largevolume;

C.cylindersarelarge,asbigasD..

2,theradiusandheightofthebottomofthecylinderareenlarged3times,anditsvolumeenlargementismultiples

A.3,B.6,C.9,D.27

3,withapieceof28.26cmlong,15.7cmwiderectangularironsheet,shouldbeequippedwithadiameter（）cmofcircularironsheet,youcanmakeavolumeofthelargestcontainer.

A.2.5B.4.5C.5D.9

Four,solvetheproblem

1,acylindricalpool,thebottomsurfaceradiusof3meters,thepoolheightof1.5meters,thepoolcanholduptohowmanytons（1cubicmetersofwaterweighing1tons）

2,acapofcylindricalmetalbucket,50cmhigh,thebottomdiameterof30cm,thebucketabouttoomuchiron?

（heretainedinteger）

3,hada1.5meterlongcylindricalwood,sawedoff4decimeterlongafterthesurfaceareadecreasedby50.24squaredecimeter.What'stheoriginalvolumeofthispieceofwood?

4,theinternaldiameterofthewaterpipeis2centimeters,thewaterflowrateofthepipeis8centimeterspersecond,howmanyliterscanthewaterflowin5minutes?

6,aworkshoptoproduce5radiusof0.6meters,20metershighcylindricalironpipe,andinitsappearancepaintedantirustpaint.By0.3kilogramspersquaremeterwithantirustpaint,howmanykilogramsshouldbeusedwithantirustpaint?

（retainadecimalnumberinoneway）

First,determinetheproblem（eachquestion1pointstotalof5points）

1.100tonsofpeanutkernelscanoil38tons,peanutoilyieldis38%tons（）.

Two

3.tworectangularbodiesofequallength,theymustbeequalinlength,width,height

Four

5.thereciprocalofallnaturalnumbersislessthan1.（）

Two,RadioButtonList（each1pointsonlyatotalof5points）

One

2.askhowmuchwateraglassfishtankcanhold,thatis,askfortheglassfishtank[...]

A.surfaceareaB.

VolumeC.,volumeD.,materialarea

3.UncleLi'stimetoprocessaparthasbeenreducedfrom10minutesto8minutes,andhisworkefficiencyhasbeenincreased

A.80%B.25%C.20%D.125%

Four

A.ishigherthanB,B.islowerthanB,C.isequaltoB.

5.a15book,morethanB5,Bthenumberofmorethanafewpercentofcorrecttypeis[]?

Three,fillintheblanks（2pointseachdayatotalof20points）

（1.）a1cubicdecimetercubecanbeplacedtogrow5wideand3decimeter