Heat Chap13095.docx
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HeatChap13095
13-95Coldwaterisheatedbyhotwaterinaheatexchanger.Thenetrateofheattransferandtheheattransfersurfaceareaoftheheatexchangeraretobedetermined.
Assumptions1Steadyoperatingconditionsexist.2Theheatexchangeriswell-insulatedsothatheatlosstothesurroundingsisnegligibleandthusheattransferfromthehotfluidisequaltotheheattransfertothecoldfluid.3Changesinthekineticandpotentialenergiesoffluidstreamsarenegligible.4Theoverallheattransfercoefficientisconstantanduniform.5Thethicknessofthetubeisnegligible.
PropertiesThespecificheatsofthecoldandhotwateraregiventobe4.18and4.19kJ/kg.C,respectively.
AnalysisTheheatcapacityratesofthehotandcoldfluidsare
Therefore,
and
Thenthemaximumheattransferratebecomes
Theactualrateofheattransferis
Thentheeffectivenessofthisheatexchangerbecomes
TheNTUofthisheatexchangerisdeterminedusingtherelationinTable13-5tobe
Thenthesurfaceareaoftheheatexchangerisdeterminedfrom
13-96"!
PROBLEM13-96"
"GIVEN"
T_cw_in=15"[C]"
T_cw_out=45"[C]"
m_dot_cw=0.25"[kg/s]"
C_p_cw=4.18"[kJ/kg-C]"
T_hw_in=100"[C],parametertobevaried"
m_dot_hw=3"[kg/s]"
C_p_hw=4.19"[kJ/kg-C]"
"U=0.95[kW/m^2-C],parametertobevaried"
"ANALYSIS"
"WithEES,itiseasiertosolvethisproblemusingLMTDmethodthanNTUmethod.Below,weuseLMTDmethod.Bothmethodsgivethesameresults."
DELTAT_1=T_hw_in-T_cw_out
DELTAT_2=T_hw_out-T_cw_in
DELTAT_lm=(DELTAT_1-DELTAT_2)/ln(DELTAT_1/DELTAT_2)
Q_dot=U*A*DELTAT_lm
Q_dot=m_dot_hw*C_p_hw*(T_hw_in-T_hw_out)
Q_dot=m_dot_cw*C_p_cw*(T_cw_out-T_cw_in)
Thw,in[C]
Q[kW]
A[m2]
60
31.35
1.25
65
31.35
1.038
70
31.35
0.8903
75
31.35
0.7807
80
31.35
0.6957
85
31.35
0.6279
90
31.35
0.5723
95
31.35
0.5259
100
31.35
0.4865
105
31.35
0.4527
110
31.35
0.4234
115
31.35
0.3976
120
31.35
0.3748
U[kW/m2-C]
Q[kW]
A[m2]
0.75
31.35
0.6163
0.8
31.35
0.5778
0.85
31.35
0.5438
0.9
31.35
0.5136
0.95
31.35
0.4865
1
31.35
0.4622
1.05
31.35
0.4402
1.1
31.35
0.4202
1.15
31.35
0.4019
1.2
31.35
0.3852
1.25
31.35
0.3698
13-97Glycerinisheatedbyethyleneglycolinaheatexchanger.Massflowratesandinlettemperaturesaregiven.Therateofheattransferandtheoutlettemperaturesaretobedetermined.
Assumptions1Steadyoperatingconditionsexist.2Theheatexchangeriswell-insulatedsothatheatlosstothesurroundingsisnegligibleandthusheattransferfromthehotfluidisequaltotheheattransfertothecoldfluid.3Changesinthekineticandpotentialenergiesoffluidstreamsarenegligible.4Theoverallheattransfercoefficientisconstantanduniform.5Thethicknessofthetubeisnegligible.
PropertiesThespecificheatsoftheglycerinandethyleneglycolaregiventobe2.4and2.5kJ/kg.C,respectively.
Analysis(a)Theheatcapacityratesofthehotandcoldfluidsare
Therefore,
and
Thenthemaximumheattransferratebecomes
TheNTUofthisheatexchangeris
EffectivenessofthisheatexchangercorrespondingtoC=0.96andNTU=2.797isdeterminedusingtheproperrelationinTable13-4
Thentheactualrateofheattransferbecomes
(b)Finally,theoutlettemperaturesofthecoldandthehotfluidstreamsaredeterminedfrom
13-98Waterisheatedbyhotairinacross-flowheatexchanger.Massflowratesandinlettemperaturesaregiven.Therateofheattransferandtheoutlettemperaturesaretobedetermined.
Assumptions1Steadyoperatingconditionsexist.2Theheatexchangeriswell-insulatedsothatheatlosstothesurroundingsisnegligibleandthusheattransferfromthehotfluidisequaltotheheattransfertothecoldfluid.3Changesinthekineticandpotentialenergiesoffluidstreamsarenegligible.4Theoverallheattransfercoefficientisconstantanduniform.5Thethicknessofthetubeisnegligible.
PropertiesThespecificheatsofthewaterandairaregiventobe4.18and1.01kJ/kg.C,respectively.
AnalysisThemassflowratesofthehotandthecoldfluidsare
Theheattransfersurfaceareaandtheheatcapacityratesare
Therefore,
and
TheNTUofthisheatexchangeris
Notingthatthisheatexchangerinvolvesmixedcross-flow,thefluidwith
ismixed,
unmixed,effectivenessofthisheatexchangercorrespondingtoC=0.2794andNTU=0.02967isdeterminedusingtheproperrelationinTable13-4tobe
Thentheactualrateofheattransferbecomes
Finally,theoutlettemperaturesofthecoldandthehotfluidstreamsaredeterminedfrom
13-99Ethylalcoholisheatedbywaterinashell-and-tubeheatexchanger.TheheattransfersurfaceareaoftheheatexchangeristobedeterminedusingboththeLMTDandNTUmethods.
Assumptions1Steadyoperatingconditionsexist.2Theheatexchangeriswell-insulatedsothatheatlosstothesurroundingsisnegligibleandthusheattransferfromthehotfluidisequaltotheheattransfertothecoldfluid.3Changesinthekineticandpotentialenergiesoffluidstreamsarenegligible.4Theoverallheattransfercoefficientisconstantanduniform.
PropertiesThespecificheatsoftheethylalcoholandwateraregiventobe2.67and4.19kJ/kg.C,respectively.
Analysis(a)Thetemperaturedifferencesbetweenthetwofluidsatthetwoendsoftheheatexchangerare
Thelogarithmicmeantemperaturedifferenceandthecorrectionfactorare
Therateofheattransferisdeterminedfrom
Thesurfaceareaofheattransferis
(b)Therateofheattransferis
Themassflowrateofthehotfluidis
Theheatcapacityratesofthehotandthecoldfluidsare
Therefore,
and
Thenthemaximumheattransferratebecomes
Theeffectivenessofthisheatexchangeris
TheNTUofthisheatexchangercorrespondingtothisemissivityandC=0.78isdeterminedfromFig.13-26dtobeNTU=1.7.Thenthesurfaceareaofheatexchangerisdeterminedtobe
Thesmalldifferencebetweenthetworesultsisduetothereadingerrorofthechart.
13-100Steamiscondensedbycoolingwaterinashell-and-tubeheatexchanger.Therateofheattransferandtherateofcondensationofsteamaretobedetermined.
Assumptions1Steadyoperatingconditionsexist.2Theheatexchangeriswell-insulatedsothatheatlosstothesurroundingsisnegligibleandthusheattransferfromthehotfluidisequaltotheheattransfertothecoldfluid.3Changesinthekineticandpotentialenergiesoffluidstreamsarenegligible.4Theoverallheattransfercoefficientisconstantanduniform.5Thethicknessofthetubeisnegligible.
PropertiesThespecificheatofthewaterisgiventobe4.18kJ/kg.C.Theheatofcondensationofsteamat30Cisgiventobe2430kJ/kg.
Analysis(a)Theheatcapacityrateofafluidcondensinginaheatexchangerisinfinity.Therefore,
andC=0
Thenthemaximumheattransferratebecomes
and
TheNTUofthisheatexchanger
ThentheeffectivenessofthisheatexchangercorrespondingtoC=0andNTU=6.76isdeterminedusingtheproperrelationinTable13-5
Thentheactualheattransferratebecomes
(b)Finally,therateofcondensationofthesteamisdeterminedfrom
13-101"!
PROBLEM13-101"
"GIVEN"
N_pass=8
N_tube=50
T_steam=30"[C],parametertobevaried"
h_fg_steam=2430"[kJ/kg]"
T_w_in=15"[C]"
m_dot_w=1800/Convert(kg/s,kg/h)"[kg/s]"
C_p_w=4.18"[kJ/kg-C]"
D=1.5"[cm],parametertobevaried"
L=2"[m]"
U=3"[kW/m^2-C]"
"ANALYSIS"
"WithEES,itiseasiertosolvethisproblemusingLMTDmethodthanNTUmethod.Below,weuseNTUmethod.Bothmethodsgivethesameresults."
"(a)"
C_min=m_dot_w*C_p_w
C=0"sincetheheatcapacityrateofafluidcondensingisinfinity"
Q_dot_max=C_min*(T_steam-T_w_in)
A=N_pass*N_tube*pi*D*L*Convert(cm,m)
NTU=(U*A)/C_min
epsilon=1-exp(-NTU)"fromTable13-4ofthetextwithC=0"
Q_dot=epsilon*Q_dot_max
"(b)"
Q_dot=m_dot_cond*h_fg_steam
Tsteam[C]
Q[kW]
mcond[kg/s]
20
10.45
0.0043
22.5
15.68
0.006451
25
20.9
0.008601
27.5
26.12
0.01075
30
31.35
0.0129
32.5
36.58
0.01505
35
41.8
0.0172
37.5
47.03
0.01935
40
52.25
0.0215
42.5
57.47
0.02365
45
62.7
0.0258
47.5
67.93
0.02795
50
73.15
0.0301
52.5
78.38
0.03225
55
83.6
0.0344
57.5
88.82
0.03655
60
94.05
0.0387
62.5
99.27
0.04085
65
104.5
0.043
67.5
109.7
0.04515
70
114.9
0.0473
D[cm]
Q[kW]
mcond[kg/s]
1
31.35
0.0129
1.05
31.35
0.0129
1.1
31.35
0.0129
1.15
31.35
0.0129
1.2
31.35
0.0129
1.25
31.35
0.0129
1.3
31.35
0.0129
1.35
31.35
0.0129
1.4
31.35
0.0129
1.45
31.35
0.0129
1.5
31.35
0.0129
1.55
31.35
0.0129
1.6
31.35
0.0129
1.65
31.35
0.0129
1.7
31.35
0.0129
1.75
31.35
0.0129
1.8
31.35
0.0129
1.85
31.35
0.0129
1.9
31.35
0.0129
1.95
31.35
0.0129
2
31.35
0.0129
13-102Coldwaterisheatedbyhotoilinashell-and-tubeheatexchanger.TherateofheattransferistobedeterminedusingboththeLMTDandNTUmethods.
Assumptions1Steadyoperatingconditionsexist.2Theheatexchangeriswell-insulatedsothatheatlosstothesurroundingsisnegligibleandthusheattransferfromthehotfluidisequaltotheheattransfertothecoldfluid.3Changesinthekineticandpotentialenergiesoffluidstreamsarenegligible.4Theoverallheattransfercoefficientisconstantanduniform.
PropertiesThespecificheatsofthewaterandoilaregiventobe4.18and2.2kJ/kg.C,respectively.
Analysis(a)TheLMTDmethodinthiscaseinvolvesiterations,whichinvolvesthefollowingsteps:
1)Choose
2)Calculate
from
3)